(x^2+2x-1)/(x-1)(x^2-x+1)
=2/(x-1)+(-x+3)/(x^2-x+1)
=2/(x-1)-(1/2)(2x-1-5)/(x^2-x+1)
=2/(x-1)-(1/2)(2x-1)/(x^2-x+1)-(5/2)/(x^2-x+1)
所以：∫(x^2+2x-1)/(x-1)(x^2-x+1)dx
∫2/(x-1)dx-(1/2)∫(2x-1)/(x^2-x+1)dx-(5/2)∫1/(x^2-x+1)dx
=2ln|x-1|-(1/2)ln(x^2-x+1)-(5/√3)arctan((2x-1)/√3)+C
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