线性代数,用克拉默法则解线性方程组

2025-02-26 08:37:08
推荐回答(1个)
回答1:

系数行列式 A =
1 -3 0 -6
2 1 -5 1
2 0 -1 2
1 4 -7 6
= 17

A1 =
9 -3 0 -6
8 1 -5 1
-5 0 -1 2
0 4 -7 6
= 177

A2 =
1 9 0 -6
2 8 -5 1
2 -5 -1 2
1 0 -7 6
= 366

A3 =
1 -3 9 -6
2 1 8 1
2 0 -5 2
1 4 0 6
= 81

A4 =
1 -3 0 9
2 1 -5 8
2 0 -1 -5
1 4 -7 0
= -179

x1 = A1/A = 177/17
x2 = A2/A = 366/17
x3 = A3/A = 81/17
x4 = A4/A = -179/17