一道求不定积分的题:x^3 ⼀ (x^2+1) dx = 应该是用换元法计算.

2024-11-25 14:46:06
推荐回答(1个)
回答1:

设t=x^2+1
∫x^3/(x^2+1) dx
= ∫(x^2)/2(x^2+1) d(x^2+1)
= ∫(t-1)/(2t) dt
= ∫(1/2)dt - ∫(1/2t)dt
= t/2 - (1/2)·lnt + C .
= (x^2+1)/2 - (1/2)·ln(x^2+1) + C.