∵x2-5x-2014=0，∴x2-5x=2014，∴原式= (x?2)3?(x?1)2+1 (x?2)2 × 2x(x?2) 2x = (x?2)3?(x?1)2+1 x?2 =（x-2）2- (x?1)2 x?2 + 1 x?2 =（x-2）2- (x?1)2?1 x?2 =（x-2）2- x(x?2) x?2 =（x-2）2-x=x2-5x+4=2014+4=2018；
