(x+2)/(x^2-2x)-(2x-1)/(x^2-4)=(1-x)/[x(x+2)](x+2)/[x(x-2)]-(2x-1)/[(x-2)(x+2)]=(1-x)/[x(x+2)]两边同乘以x(x-2)(x+2)(x+2)^2-(2x-1)x=(1-x)(x-2)x^2+4x+4-(2x^2-x)=x-2-x^2+2x-x^2+5x+4=3x-2-x^22x=-6x=-3
x = -3
