电路如图所示,其中Us=10V,Is=4A,R1=R2=2,C=5F。 开关闭合前电路已达稳态,求S闭合后电容电压uC。

需要详细的解题过程哦~~~O(∩_∩)O谢谢!!!!
2024-12-28 12:52:10
推荐回答(1个)
回答1:

Uc(0+) = Uc(0-) = Is * (R1+R2) = 16V

S 闭合后:

用戴维南定理化简:

Uab = Is * R1 - Us1 = -2V

Rab = R1 = 2Ω

Uc(∞) = -2V

τ = Rab * C = 10

三要素法:

Uc = -2 + (16 +2)e^-t/10

     = -2 + 18e^-0.1t