等差数列an的前n项和为sn,且满足s四加a25等于五,则一定有

2025-04-02 11:47:08
推荐回答(1个)
回答1:

S4+a25
=4a1+6d+a1+24d
=5a1+30d
=5(a1+6d)
=5a7
5a7=5
a7=1
S13=(a1+a13)×13/2=2a7×13/2=2×1×13/2=13,为定值
选D