计算∫xcos눀xdx

2025-03-10 22:09:18
推荐回答(1个)
回答1:

∫xcos²xdx
=∫x((cos2x+1)/2)dx
=∫(cos2x+1)/2xdx+∫x/2dx
=∫x/4dsin2x+x²/4
=xsin2x/4+cos2x/2+x²/4