求导数,给出详细过程y=e^{根号下【1-sin(1⼀x)】}

2025-03-18 20:26:06
推荐回答(2个)
回答1:

y=e^{根号下【1-sin(1/x)】}

y'=e^{根号下【1-sin(1/x)】}*{根号下【1-sin(1/x)】}'

  =e^{根号下【1-sin(1/x)】}*1/{2根号下【1-sin(1/x)】}*【1-sin(1/x)】'

  =e^{根号下【1-sin(1/x)】}*1/{2根号下【1-sin(1/x)】}*【-cos(1/x)】*(1/x)'

  =e^{根号下【1-sin(1/x)】}*1/{2根号下【1-sin(1/x)】}*cos(1/x)*(1/x^2)

回答2:

如图