(2014?泰州模拟)如图,在三棱柱ABC-A1B1C1中,AB⊥AC,顶点A1在底面ABC上的射影恰为点B,且AB=AC=A1B=2

2025-01-02 05:24:13
推荐回答(1个)
回答1:

解:(1)如图,以A为原点建立空间直角坐标系,
则C(2,0,0),B(0,2,0),A1(0,2,2),
B1(0,4,2),

AA1
=(0,2,2),
BC
B1C1
=(2,?2,0)
cos?
AA1
BC
>=
AA1
?
BC
|
AA1
|?|