shell如何删除文本中每行特定字符串到行尾的内容？

cd $AICBS22/vgroup/busivpmn/server/atmi/;gmake -f Makefile.test clean;gmake -f Makefile.test cd $AICBS22/vgroup/busivpmn/server/atmi/test/source/;gmake -f Makefile clean;gmake -f Makefile cd $AICBS22/vgroup/busivpmn/server/mgr/;gmake -f Makefile clean;gmake -f Makefile cd $AICBS22/vgroup/busivpmn/server/mgr/;gmake -f Makefile.mml clean;gmake -f Makefile.mml cd $AICBS22/vgroup/busivpmn/server/mgr/;gmake -f Makefile.res clean;gmake -f Makefile.res cd $AICBS22/vgroup/busivpmn/server/pmgr/;gmake -f Makefile clean;gmake -f Makefile cd $AICBS22/vgroup/busivpmn/server/pmgr/;gmake -f Makefile.intf clean;gmake -f Makefile.intf cd $AICBS22/vgroup/busivpmn/server/releaseVpmnPhone/;gmake -f Makefile clean;gmake -f Makefile cd $AICBS22/vgroup/busivpmn/server/svr/;gmake -f Makefile clean;gmake -f Makefile cd $AICBS22/vgroup/busivpmn/server/svr/;gmake -f Makefile.svr1 clean;gmake -f Makefile.svr1 cd $AICBS22/vgroup/busivpmn/server/syncvnextprod/;gmake -f Makefile clean;gmake -f Makefile cd $AICBS22/vgroup/busivpmn/server/vpmnAsyncNextProd/;gmake -f Makefile clean;gmake -f Makefile 请各位老大看看这么写个shell。可以将每行中字符串clean后面的内容都去掉。 最后结果变为 cd $AICBS22/vgroup/busivpmn/server/atmi/;gmake -f Makefile.test clean 。。。省略