a=√3+√3/√2-√2b=√3-√3/√2+√2a-b=√6-2√2, ab=(√3+√3/√2-√2)[√3-(√3/√2-√2)]=3-(√3/√2-√2)�0�5=2√3-1/2a�0�5—3ab+b�0�5=(a-b)�0�5-ab=(√6-2√2)�0�5-(2√3-1/2)=6+8-8√3-12-1/4+2√3=7/4-6√3呼...同学,你们老师下手挺狠的...