解：原式=<2（x+3)/2(x�0�5-9)-12/2(x�0�5-9)-(x-3)(x-1)/2(x�0�5-9)>÷(x-3）�0�5/2(x+3) = (2x+6-12-x�0�5 +4x-3)/2(x�0�5-9)*2(x+3)/(x-3)�0�5 =(-x�0�5+6x-9)/2(x�0�5-9)*2(x+3)/(x-3)�0�5 =-(x�0�5-6x+9)/2(x�0�5-9)*2(x+3)/(x-3)�0�5 =-1/(x-3)谢谢采纳！
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