ajax读取json显示undefined

2025-02-22 12:50:25
推荐回答(1个)
回答1:


var a = '[{"supp_Id":"2","prod_No":"1","prod_Name":"钢笔","prod_Model":"小型","prod_Unit":"往往外","proT_ID":"1","proMin":"2","proMax":"6","prod_Status":"0","prod_Remark":"2","prod_Ucers":"2","prod_Prices":2,"prot_Name":"圆珠笔","inventory_Num":"1.0"},{"supp_Id":"2","prod_No":"2","prod_Name":"1","prod_Model":"1","prod_Unit":"1","proT_ID":"1","proMin":"2","proMax":"8","prod_Status":"0","prod_Remark":"2","prod_Ucers":"2","prod_Prices":2,"prot_Name":"圆珠笔","inventory_Num":"10.0"}]';

var b = eval('(' + a + ')');

for(var i=0;i    alert(b[i].prod_No);
}

我测试了你的代码,确实是可以alert出值的,和大小写有没有关系呢,因为我发现你的json数据和处理函数的大小写不一样。