已知cos(a-b⼀2)= -1⼀9,sin(a⼀2-b)=2⼀3,且π⼀2<a<π,0<b<π⼀2,求cos(a+b)的值

2025-01-05 17:06:05
推荐回答(1个)
回答1:

先算cos[(a+b)/2]=cos(a-b/2)cos(a/2-b)+sin(a-b/2)sin(a/2-b)
再算cos(a+b)=2*cos^2[(a+b)/2]-1即可
得到cos(a+b)=-239/729