匀速圆周运动，因为r =10cos5ti+10sin5tj，设X=10cos5ti,Y=10sin5tj,等式两边都平方的r^2=(10cos5ti)^2+(10sin5tj)^2=100,其中10cos5ti*10sin5tj=0,即X^2+Y^2=100,因此为匀速圆周运动。
