(1+1⼀2)(1+1⼀2的2次方)(1+1⼀2的4次方)(1+1⼀2的8次方)+1⼀2的15次方请大神写出详细过程

2025-01-06 17:37:13
推荐回答(3个)
回答1:

多乘一个(1-1/2)

原式:2(1-1/2)(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^15

=2(1-1/2^2)(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^15

=2(1-1/2^4)(1+1/2^4)(1+1/2^8)+1/2^15

=2(1-1/2^8)(1+1/2^8)+1/2^15

=2(1-1/2^16)+1/2^15

=2-1/2^15+1/2^15

=2

希望可以帮到你,还望及时采纳 谢谢、O(∩_∩)O~~

回答2:

(1+2分之1)(1+2的平方分之1)(1+2的四次方分之)(1+2的八次方分之1)+1/2的15方
=2*(1-1/2)(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^15
=2*(1-1/2^2)(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^15
=2*(1-1/2^4)(1+1/2^4)(1+1/2^8)+1/2^15
=2*(1-1/2^8)(1+1/2^8)+1/2^15
=2(1-1/2^16)+1/2^15
=2-1/2^15+1/2^15
=2

回答3:

(1+1/2)(1+1/2的2次方)(1+1/2的4次方)(1+1/2的8次方)+1/2的15次
=1/(1-1/2)*(1-1/2)(1+1/2)(1+1/2的2次方)(1+1/2的4次方)(1+1/2的8次方)+1/2的15次
=2*(1-1/2的2次方)(1+1/2的2次方)(1+1/2的4次方)(1+1/2的8次方)+1/2的15次
=...
=2*(1-1/2的16次方)+1/2的15次
=2