1-2^2-3^2+4^2+5^2-6^2-7^2+……+24^2

2024-12-19 05:48:49
推荐回答(3个)
回答1:

解:1-2²-3²+4²+5²-......-22²-23²+24²
=(4²-3²)-(2²-1²)+(8²-7²)-(6²-5²)+......+(24²-23²)-(22²-21²)
然后根据完全平方公式a²-b²=(a+b)(a-b),得
原式=(4+3)(4-3)-(2+1)(2-1)+(8+7)(8-7)-(6+5)(6-5)+......+(24+23)(24-23)-(22+21)(22-21)
=(4+3)×1-(2+1)×1+(8+7)×1-(6+5)×1+......+(24+23)×1-(22+21)×1
=4+3-2-1+8+7-6-5+......+24+23-22-21
=(4-2)+(3-1)+(8-6)+(7-5)+......+(24-22)+(23-21)
=2+2+......+2 (12个2)
=24

望采纳,谢谢!

回答2:

解:1-2²-3²+4²+5²-......-22²-23²+24²
=(4²-3²)-(2²-1²)+(8²-7²)-(6²-5²)+......+(24²-23²)-(22²-21²)
然后根据完全平方公式a²-b²=(a+b)(a-b),得
原式=(4+3)(4-3)-(2+1)(2-1)+(8+7)(8-7)-(6+5)(6-5)+......+(24+23)(24-23)-(22+21)(22-21)
=(4+3)×1-(2+1)×1+(8+7)×1-(6+5)×1+......+(24+23)×1-(22+21)×1
=4+3-2-1+8+7-6-5+......+24+23-22-21
=(4-2)+(3-1)+(8-6)+(7-5)+......+(24-22)+(23-21)
=2+2+......+2 (12个2)
=24

回答3:

原式=(4+3)(4-3)-(2+1)(2-1)+(8+7)(8-7)-(6+5)(6-5)+......+(24+23)(24-23)-(22+21)(22-21)
=(4+3)×1-(2+1)×1+(8+7)×1-(6+5)×1+......+(24+23)×1-(22+21)×1
=4+3-2-1+8+7-6-5+......+24+23-22-21
=(4-2)+(3-1)+(8-6)+(7-5)+......+(24-22)+(23-21)
=2+2+......+2 (12个2)
=24