51问答网 > 两列火车同时从甲乙两地相对开出.快车行完全程需要20小时，慢车行完全程需要30小时，已知快车中途停留2小

两列火车同时从甲乙两地相对开出.快车行完全程需要20小时，慢车行完全程需要30小时，已知快车中途停留2小

时，慢车停留1小时。则两车开出后多少小时才相遇
2025-04-07 19:39:09
推荐回答（3个）
回答1：

因为快车停2小时，慢车停1小时，相当于慢车提前走1小时，走全程的1/30，余下的两车共走时间：（1-1/30）/（1/30+1/20）=11.6小时。所以，两车开出后11.6+2=13.6小时相遇

回答2：

设路程为s,两车开出后t小时才相遇

快车速度为s/20;慢车速度为s/30
s/20(t-2)+s/30(t-1)=s
t=68/5

回答3：

（1+1/20×2+1/30）÷（1/20+1/30）
=17/15÷1/12
=13.6小时

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