已知x+2y-3z=0,2x+3y+5z=0,且x,y,z都不为0,求(x+y+z)除以(x-y+z)

2024-12-31 05:16:32
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回答1:

解:x + 2y = 3z①,2x + 3y = -5z②,联立解得y = 11z和x = -19z,代入可得,原式 = (-19z + 11z + z) / (-19z - 11z + z) = -7z / (-29z) = 7/29,即原式 = 7/29 。