计算:(x-1⼀2)(1-3⼀2x)눀-x(2+x⼀4)눀 详细过程

2024-12-29 11:22:24
推荐回答(1个)
回答1:

(x-1/2)(1-3/2x)²-x(2+x/4)²
=1/8(2X-1)(2X-3)²-1/16X(8+X)²
=1/16[2(2X-1)(4X^2-12X+9)-X(X^2+16X+64)]
=1/16[16X^3-56X²+60X-18-X^3-16X²-64X]
=15/16X^3-9/2X²-1/4X-9/8。