x=sqrt((3+2√2)/6)，对吧？x=(√2+1)/√61-x^2=1-(3+2√2)/6=(3-2√2)/6=(√2-1)^2/6x/sqrt(1-x^2)+sqrt(1-x^2)/x=1/(xsqrt(1-x^2))=1/((√2+1)(√2-1)/6)=6
