x^2-x-1=0,求代数式x^3-2x+1的值

2024-12-28 01:25:36
推荐回答(2个)
回答1:

解:因为x^2-x-1=0,所以x^2=x+1,x^2-X=1,
x^3-2x+1
=x^2*x-2x+1
=(x+1)x-2x+1
=x^2+x-2x+1
=x^2-x+1
=1+1
=2

回答2:

x^3-2x+1=x(x^2-x-1)+(x^2-x-1)+2=0+0+2=2