①(2a⼀a-1-a⼀a+1)*a눀-1⼀a ②(x+2⼀x눀-2x-x-1⼀x눀-4x+4)÷x-4⼀x

2024-11-25 11:51:10
推荐回答(2个)
回答1:

①(2a/a-1-a/a+1)*a²-1/a
=[2a(a+1)-a(a-1)]/(a-1)(a+1)* a²-1/a
=[2a²+2a-a²+a)]/(a²-1)* a²-1/a
=[a²+3a]/a
=a+3
②(x+2/x²-2x-x-1/x²-4x+4)÷x-4/x
=[(x+2)/x(x-2) -x-1/(x-2)²] *x/(x-4)
={[(x+2)(x-2) -x(x-1)]/x(x-2)²} *x/(x-4)
={[x²-4-x²+x]/x(x-2)²} *x/(x-4)
=[(x-4)/x(x-2)²] *x/(x-4)
=1/(x-2)²

回答2:

①【2a(a+1) - a(a-1)】÷(a² -1)(a² -1)/a=a+3
②【(x+2) (x-2)/x(x-2)² - (x-1)x/x(x-2)²】×x/(x-4)
=【(x-4)/x(x-2)²】×x/(x-4)
=1/(x-2)²