x的四次方-6x的2次方+1(因式分解)
x^4-6x^2+1
=x^4-6x^2+9-8
=(x^2-3)^2-8
=(x^2-3+2√2)(x^2-3-2√2)
=[x^2-(1-2√2+2)][x^2-(1+2√2+2)]
=[x^2-(1-√2)²][x^2-(1+√2)²]
=(x+1-√2)(x-1+√2)(x+1+√2)(x-1-√2)
4x的四次方+1(同上)
=4x^4+1
=4x^4+4x^2+1-4x^2
=(2x^2+1)²-4x^2
=(2x^2+1+2x)(2x^2+1-2x)
=(2x^2+2x+1)(2x^2-2x+1)
a的三次方+a²+a-3(同上)
=a³+a²+a-3
=a³-a²+2a²-2a+3a-3
=a²(a-1)+2a(a-1)+3(a-1)
=(a-1)(a²+2a+3)
(a+b)²-2(1+a+b)-1
=(a+b)²-2-2(a+b)-1
=(a+b)²-2(a+b)-3
=(a+b+1)(a+b-3)
x²-4(1+xy)+4y²
=x²-4-4xy+4y²
=x²-4xy+4y²-4
=(x-2y)²-4
=(x-2y+2)(x-2y-2)
12a²-8a-15
=(2a-3)(6a+5)
好复杂 我是来混经验的 谢谢