已知x2-x-1=0,则代数式(x3-2x+1)2的值为?

2024-11-26 20:47:28
推荐回答(1个)
回答1:

因为x^2-x-1=0,所以x^2=x+1,x^2-X=1,
x^3-2x+1
=x^2*x-2x+1
=(x+1)x-2x+1
=x^2+x-2x+1
=x^2-x+1
=1+1
=2
所以(x3-2x+1)2=4