cosπ⼀7+cos3π⼀7+cos5π⼀7 =?

2025-01-04 08:55:04
推荐回答(2个)
回答1:

cosπ/7+cos3π/7+cos5π/7
=(sinπ/7cosπ/7+sinπ/7cos3π/7+sinπ/7cos5π/7)/sinπ/7
=[sin2π/7+(sin4π/7-sin2π/7)+(sin6π/7-sin4π/7)]/(2sinπ/7) 括号里用积化和差
=sin6π/7/(2sinπ/7)
=sin(π-π/7)/(2sinπ/7)
=sinπ/7/(2sinπ/7)
=1/2

回答2:

cosπ/7+cos3π/7+cos5π/7
=cosπ/7+cos3π/7-cos(π-5π/7) (利用公式 cos(A)=-cos(π-A))
=cosπ/7+cos3π/7-cos(3π/7)
=cosπ/7