x^3-y^3＝（x+y）（x^2+xy+y^2）=0
x³-y³=(x-y)(x²+xy+y²)=(x-y)×0=0不懂的欢迎追问,如有帮助请采纳，谢谢!
x³-y³=(x-y)(x²+xy+y²)=0
