=(x+1)(x-1)/(x-1)²-x(x-2)/(x-2)×1/x
=(x+1)/(x-1)-1
=(x+1-x+1)/(x-1)
=2/(x-1)
当x=√5-1时
原式=2/(√5-2)=2(√5+2)=2√5+4
(x²-1/x²-2x+1)-(x²-2x/x-2)÷x
=(x+1)(x-1)/(x-1)^2-x(x-2)/x(x-2)
=(x+1)/(x-1)-1
=(√5-1+1)/(√5-1-1)-1
=√5/(√5-2)-1
=5+2√5-1
=4+2√5
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谢谢
原式=(x+1)(x-1)/(x-1)²-x(x-2)/(x-2)÷x
=(x+1)/(x-1)-x÷x
=(x+1)/(x-1)-1
=(x+1-x+1)/(x-1)
=2/(x-1)
=2/(√5-2)
=2(√5+2)/(5-4)
=2√5+4
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