高中物理气缸问题

答案已标在图中,过程不会。求详解。
2024-12-23 01:32:36
推荐回答(2个)
回答1:

1.kl所以缸内压强为P1=P0+kl/S
气体体积为,V=2lS
又因为P0*V0/T0=P1*V1/T1
即P0*lS/T0=(P0+kl/S)*2lS/T1
得T1=2(P0+kl/S)*T0/P0
2,(这TM就是一个扯淡的题目,静摩擦力大于动摩擦力,照题中显示缓慢运动明显是动摩擦力,这里权当两者相等)kl>f 则当弹簧还未运动到缸口时,kl=f,弹簧保持静止,气缸开始运动,当气缸运动指导活塞位于缸口时,缸体内气体所受的压力为f,所以缸内压强为P2=P0+f/S
气体体积为,V=2lS
又因为P0*V0/T0=P2*V2/T2
即P0*lS/T0=(P0+f/S)*2lS/T1
得T1=2(P0+f/S)*T0/P0

回答2:

(1)当klP0×V÷T0= P1×2V÷T1
所以T1=(P1×2V×T0)÷(P0×V)
= 2(P0+ kl÷S)×T0÷P0

(2)当kl>f时,活塞移动至缸口,缸内气体压强为P1= P0+ f÷S(此时气缸已经移动)
P0×V÷T0= P1×2V÷T1
所以T1=(P1×2V×T0)÷(P0×V)
= 2(P0+ f÷S)×T0÷P0

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