【【解分式方程】】:x⼀(x-2) - (x-1)⼀(x^2-5x+6)=2⼀(x-3)

2024-12-12 06:37:30
推荐回答(1个)
回答1:

x/(x-2) - (x-1)/(x²-5x+6)=2/(x-3)
∵x²-5x+6=(x-2)*(x-3)≠0
∴x≠2,且x≠3
两边同时乘以(x-2)*(x-3)得
X(x-3)-(x-1)=2(x-2)
X²-3x-x+1=2x-4
X²-6x+5=0
(x-1)*(x-5)=0
x-1=0,或x-5-0
x=1,或x=5