y=1+sin(2x+pai⼀4)的递减区间

2025-03-22 14:01:39
推荐回答(3个)
回答1:

2kπ<(2x+π/4)<2kπ+π/2;2kπ+3π/2<(2x+π/4)<2kπ+2π剩下就是解放程

回答2:

X属于【2Kpai+pai/8,2Kpai+5pai/8】,K属于Z

回答3:

pai/2+2kpai<=2x+pai/4<=3pai/2+2kpai
pai/4+2kpai<=2x<=5pai/4+2kpai
pai/8+kpai<=x<=5pai/8+kpai