先化简再求值(1+1⼀x눀-1)÷(x-x⼀x+1),其中x=√2+1

2025-01-03 20:23:25
推荐回答(1个)
回答1:

解:(1+1/x²-1)÷(x-x/x+1)
=(x²-1+1)/(x+1)(x-1)÷(x²+x-x)/(x+1)
=x²/(x+1)(x-1)×(x+1)/x²
=1/(x-1)
将x=√2+1代入得
原式=1/√2=√2/2

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