在实数范围内分解因式(1) 2x눀+2x-1 (2)x눀-2xy-y눀

2024-11-24 16:43:42
推荐回答(2个)
回答1:

1.2x²尘逗+2x-1
=2(x²+x-1/2)
=2(x²+x+1/4-3/4)
=2[(x+1/2)²迅没-3/4]
=2(x+1/2+√3/2)(x+1/2-√3/2)
(2)派昌卖x²-2xy-y²
=(x²-2xy+y²)-2y²
=(x-y)²-2y²
=(x-y+√2y)(x-y-√2y)

回答2:

(1) 2x²+2x-1
=2(x²+x-1/颤和袭2)
=2(x²+x+1/4-3/4)
=2[(x+1/2)²-3/4]
=2(x+1/2+√3/2)(x+1/2-√茄兄3/2)

(2)x²-2xy-y²
=(x²-2xy+y²棚掘)-2y²
=(x-y)²-2y²
=(x-y+√2y)(x-y-√2y)