先化简再求值(x^2+4⼀x -4)⼀x^2-4⼀x62+2x其中x=-1

2024-12-20 15:59:38
推荐回答(1个)
回答1:

[(x^2+4)/(x -4)]/[(x^2-4)/(x^2+2x)]
=[(x^2+4)/(x -4)]*(x^2+2x)/(x^2-4)
=[(x^2+4)/(x -4)]*x(x+2)/[(x-2)(x+2)]
=[(x^2+4)/(x -4)]*x/(x-2)
=x(x^2+4)/[(x -4)(x-2)]
=x(x^2+4)/(x^2-6x+8)