解下列三元一次方程组: (1)x-z=4,x+y-z=-1,2y-z=1 (2)3x+4z=7,2x+3y+z=9,x-y+z=8

2024-11-27 06:14:22
推荐回答(3个)
回答1:

(1)x-z=4,①
x+y-z=-1,②
2y-z=1 ③

②-①得:

y=-5 代入③:
-10-z=1
-z=11
z=-11 代入①:
x+11=4
x=-7
所以,x=-7, y=-5,z=-11

回答2:

1 z=x-4
x+y-(x-4)=-1,y=-5
2×5-z=1,z=9
x-9=4,x=13
2 x=8+y-z
3(8+y-z)+4z=7,z=-17-3y,x=25+4y
50+8y+3y-17-3y=9 y=-3 x=13 z=-8

回答3:

x-z=4 x+y=-1+z2y=1+z x=7 y=4 z=9