已知x1、x2为方程x눀+3x+1=0的两实根,则x1눀+8x2+20=_______(已知答案为-1) 求解答过程

2024-12-18 02:12:04
推荐回答(1个)
回答1:

x1²+3x1+1=0
x1²=-3x1-1
所以x1³
=x1(-3x1-1)
=-3x1²-x1
=-3(-3x1-1)-x1
=8x1+3

且x1+x2=-3
所以原式=8x1+3+8x2+20
=8(x1+x2)+23
=-24+23
=-1