分解因式: x^3-2x^2y+xy^2-x。a^7-a^5b^2+a^2b^5-b^7。

2024-12-22 01:52:03
推荐回答(1个)
回答1:

你好

x^3-2x^2y+xy^2-x
=x(x^2-2xy+y^2-1)
=x[(x-y)^2-1)]
=x[(x-y)+1)][(x-y)-1)]
=x(x-y+1)(x-y-1)

a^7-a^5b^2+a^2b^5-b^7
=a^5(a^2-b^2)+b^5(a^2-b^2)
=(a^5+b^5)(a^2-b^2)
=(a+b)(a^4-a^3b+a^2b^2-ab^3+b^4)(a+b)(a-b)
=(a-b)(a+b)^2(a^4-a^3b+a^2b^2-ab^3+b^4)

【数学辅导团】为您解答,不理解请追问,理解请及时选为满意回答!(*^__^*)谢谢!