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51问答网 > 计算：1⼀（√3+√2）+1⼀（√2+1）-1⼀√3+1

计算：1⼀（√3+√2）+1⼀（√2+1）-1⼀√3+1

要详细过程

2024-12-28 07:23:13

推荐回答（3个）

回答1：

1/(√3+√2)+1/(√2+1)-1/√3+1
=(√3-√2)/[(√3+√2)(√3-√2)]+(√2-1)/[(√2+1)(√2-1)]-1/√3+1
=(√3-√2)+(√2-1)-1/√3+1
=√3-√2+√2-1-1/√3+1
=√3-1/√3
=√3-√3/3
=2√3/3

回答2：

1/（√3+√2）+1/（√2+1）-1/√3+1

=（√3-√2﹚／[﹙√3+√2﹚﹙√3-√2﹚]+﹙√2-1）／[﹙√2+1）（√2-1）]-（√3-1）／[﹙√3+1）（√3-1）]
=√3-√2+√2-1-（√3-1）／2
=（√3-1）／2

回答3：

1/（√3+√2）+1/（√2+1）-1/√3+1
=（√3-√2)+（√2-1）-(√3-1)/2
=(√3-1)/2

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