已知x=1⼀2(根号7+根号5) y=1⼀2(根号7-根号5),求x^2-xy+y^2的值

2024-12-23 04:39:02
推荐回答(3个)
回答1:

X^2-xy+y^2=(x-y)^2=(1/2根号7+1/2根号5-1/2根号7+1/2根号5)^2=(根号5)^2=5

回答2:

x^2-xy+y^2=(x-y)^2+xy
x-y=根号5 xy=1/2
所以原式=(x-y)^2+xy=(根号5)^2+1/2=11/2

回答3:

x2-xy+y2=x2-xy-xy+y2+xy=(x-y)2+xy.因为x-y=根号5.xy=1/2.所以x2-xy+y2=5+1/2=5.5