解方程(1)(3x-1⼀2)=1-(2x+1⼀6 (2)(x-3⼀0.5)-(x+4⼀0.2)=1 (3)(x+4⼀5)-{x-5}=(x+2⼀3)-(x-2⼀2

2024-11-25 17:57:54
推荐回答(1个)
回答1:

(1)(3x-1)/2=1-(2x+1)/6
3(3x-1)=6-(2x+1)
9x-3=6-2x-1
11x=8
x=8/11

(2)(x-3)/0.5-(x+4)/0.2=1
2(x-3)-5(x+4)=1
2x-6-5x-20=1
3x=-27
x=-9

(3)(x+4)/5-(x-5)=(x+2)/3-(x-2)/2
6(x+4)-30(x-5)=10(x+2)-15(x-2)
6x+24-30x+150=10x+20-15x+30
19x=124
x=124/19