平方差公式展开=101^2-[(100-99)+(98-97)+...+(2-1)]=101^2-5050=10201-5050=5151
=(1+2)(1-2)+(3+4)(3-4)+···········(99+100)(99-100)+101·101=-(1+2+3+4+``````````````````99+100)+101·101=-(1+100)·100/2+101·101=101·101-101·50=101·51=5151