(1⼀2+1⼀3+......+1⼀2013)*1+1⼀2+...1⼀2014)-(1+1⼀2+...+1⼀2013)*(1⼀2+1⼀3+...+1⼀2014

2024-12-28 03:51:02
推荐回答(1个)
回答1:

解:
为方便计算,令1/2+1/3+...+1/2013=m
原式=m(1+m+ 1/2014)-(1+m)(m+ 1/2014)
=m+m²+ m/2014 -m²-m- m/2014 -1/2014
=-1/2014