已知x대=10-y대,x눀y-xy눀=-3,求代数式

2024-12-28 08:36:37
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回答1:

题目问的应该是(x^3-y^3)-(2x^2y-4xy^2)-2(-y^3+xy^2)的值x^3=10-y^3,x^2y-xy^2=-3
则x^3+y^3=10,x^2y-xy^2=-3

(x^3-y^3)-(2x^y-4xy^2)-2(-y^3+xy^2)
=x^3-y^3-2x^y+4xy^2+2y^3-2xy^2
=x^3+y^3-2x^y+2xy^2
=(x^3+y^3)-2(x^y-xy^2)
=10+6
=16