已知x=(√3-√2)÷(√3+√2) y=(√3+√2)÷(√3-√2)求x÷(x-√xy)-√y÷(√x+√y)的值

x=(√3-√2)÷(√3+√2)
x=[(√3-√2)(√3-√2)]÷[(√3+√2)(√3-√2)]
x=(5-2√6)
y=(√3+√2)÷(√3-√2)

y=[(√3+√2)(√3+√2)]÷[(√3+√2)(√3-√2)]
y=5+2√6
x÷(x-√xy)-√y÷(√x+√y)的值

=x÷[√x(√x-√y)]-[√y(√x-√y)]÷[(√x+√y)(√x-√y)]
=√x/(√x-√y)-√y(√x-√y)/[(√x+√y)(√x-√y)]
=[√x(√x+√y)-√y(√x-√y)]/[(√x+√y)(√x-√y)]
=[x+√xy-√xy+y]/[(√x+√y)(√x-√y)]
=(x+y)/(x-y)
=(5-2√6 +5+2√6)/(5-2√6 -5-2√6)
=10/(-4√6)
=-5√6/12

x=(√3-√2)÷(√3+√2)=(√3-√2)^2=5-2√6
y=(√3+√2)÷(√3-√2)=(√3+√2)^2=5+2√6
√xy=√(√3-√2)(√3+√2)=1
x÷(x-√xy)-√y÷(√x+√y)=x/(x-1)-√y(√x-√y)/(√x+√y)(√x-√y)
=x/(x-1)-√y(√x-√y)/(x-y)
=x/(x-1)-(√xy-y)/(x-y)
=(5-2√6)/(4-2√6)-(1-5-2√6)/(-4√6)
=(5-2√6)(4+2√6)/(-8)+(4+2√6)/(-4√6)
=-1/4√6+1/2-1/6√6-1/2
=-5/12√6

根据提议得x=1/y
x÷(x-√xy)-√y÷(√x+√y)
=x/(x-1)-√y√x÷(√x+√y)√x
=x/(x-1)-1/(x+1)
=1/(1-y)-1/(x+1)
又因为
x=(√3-√2)÷(√3+√2)
x=[(√3-√2)(√3-√2)]÷[(√3+√2)(√3-√2)]
x=(5-2√6)
y=(√3+√2)÷(√3-√2)

y=[(√3+√2)(√3+√2)]÷[(√3+√2)(√3-√2)]
y=5+2√6

原式=1/（1-5-2√6）-1/(1+5+2√6)
=1/(-4-2√6)-1/(6+2√6)
=(-5-2√6)/(24+10√6)