化简求值:已知x=1⼀2(根号7+根号5),y=1⼀2(根号7-根号5),求x+y的值,求x的平方-XY+Y的平方

2025-01-07 15:50:40
推荐回答(3个)
回答1:

x=1/2(√7+√5),y=1/2(√7-√5)

x+y=1/2(√7+√5+√7-√5)=√7

x^2-xy+y^2
=(x-y)^2+xy
=5+1/4(√7+√5)(√7-√5)
=5+1/2
=11/2

补充:Native speakers often speak too (fast)

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回答2:

x+y=1/2(√7+√5)+1/2(√7-√5)=√7
x^2-xy+y^2=(x-y)^2+xy
={1/2(√7+√5)-1/2(√7-√5)}^2+{1/2(√7+√5)}*{1/2(√7-√5)}
=5+1/4(7-5)
=5+1/2
=5.5

回答3: