若有理数x、y、满足(x-1)²+(2x-y)⁴+(x-3z)²=0，(x-1)=0 (2x-y)=0 (x-3z)=0x=1 y=2 z=1/3x+y+z的值=1+2+1/3=10/3
(x-1)=0 (2x-y)=0 (x-3z)=0x=1 y=2 z=1/3x+y+z的值=1+2+1/3=10/3
3个平方相加等于0，每个都是0x=1,y=2,Z=3x+y+z=6
