(2+4u)/(2-7u-4u^2)=(2+4u)/(2+u)(1-4u)=(4/3)/(2+u)-(4/9)/(1-4u)
∫(2+4u)/(2-7u-4u^2)du
=∫(-2/3)/(2+u)du+∫(4/3)/(1-4u)du
=(-2/3)ln|2+u|-(1/3)ln|1-4u|+C
2(2U+1)/(U-4)(2U+1)=2/(U-4)
∫(2+4u)/(2-7u-4u^2)
=-∫(2+4u)/(u+2)(4u-1)
=-2/3∫（2/(4u-1)+1/(u+2)）du
=-1/3ln│4u-1│-2/3ln│u+2│+C
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