1.2.1 相对界限受压区高度 ξb = β1 / [1 + fy / (Es * εcu)]
= 0.8/[1+360/(200000*0.0033)] = 0.518
1.2.2 单筋矩形截面或翼缘位于受拉边的T形截面受弯构件受压区高度 x 按下式计算:
x = ho - [ho ^ 2 - 2 * M / (α1 * fc * b)] ^ 0.5
= 430-(430^2-2*250000000/1/14.33/200)^0.5
= 328mm > ξb * ho = 0.518*430 = 223mm
当 x > ξb * ho 时,钢筋应力 σs = Es * εcu * (β1 * ho / x - 1)
σs = 200000*0.0033*(0.8*430/328-1) = 33N/mm
1.2.3 As = α1 * fc * b * x / σs = 1*14.33*200*328/33 = 28678mm
“我不学这个 看不懂....”那就不用回答了。写出来您还是看不懂