用加减法解方程组:{(x+y)⼀6+(x-y)⼀10=3 (x+y)⼀6+(y-x)⼀10=-1

2024-12-29 01:48:07
推荐回答(1个)
回答1:

(x+y)/6+(x-y)/10=3 ①
(x+y)/6+(y-x)/10=-1 ②
①可变为:(x+y)/6-(y-x)/10=3 ③
②+③=(x+y)/3=2
得x+y=6 ④
②-③=(y-x)/5=-4
得y-x=-20 ⑤
④+⑤=2y=-14
得 y=-7
④-⑤=2x=26
得x=13